1_03

辽宁师范大学 • 张大为@https://daweizh.github.io/noip/

1.3 编程基础之算术表达式与顺序执行(20)

A+B问题，http://noi.openjudge.cn/ch0103/01/[+]

#include <iostream>
using namespace std;

int main() {
    int a,b;

    cin >>a >> b;
    cout << a+b << endl;
    
    return 0;
}

计算(a+b)*c的值，http://noi.openjudge.cn/ch0103/02/[+]

#include <iostream>
using namespace std;

int main() {
    int a,b,c;
    
    cin >>a >> b >> c;
    cout << (a+b)*c << endl;
    
    return 0;
}

计算(a+b)/c的值，http://noi.openjudge.cn/ch0103/03/[+]

#include <iostream>
using namespace std;

int main() {
    int a,b,c;
    
    cin >>a >> b >> c;
    cout << (a+b)/c << endl;
    
    return 0;
}

带余除法，http://noi.openjudge.cn/ch0103/04/[+]

#include <iostream>
using namespace std;

int main() {
    int a,b;
    
    cin >>a >> b ;
    cout << a/b << " " << a % b << endl;
    
    return 0;
}

计算分数的浮点数值，http://noi.openjudge.cn/ch0103/05/[+]

#include <iostream>
#include<iomanip>
using namespace std;

int main() {
    double a,b;
    
    cin >>a >> b ;
    cout << fixed << setprecision(9) << a/b << endl;
    
    return 0;
}

甲流疫情死亡率，http://noi.openjudge.cn/ch0103/06/[+]

#include <iostream>
using namespace std;

int main() {
    double a,b;
    
    cin >>a >> b ;
    printf("%.3f%%",b*100/a);
    
    return 0;
}

计算多项式的值，http://noi.openjudge.cn/ch0103/07/[+]

#include <iostream>
using namespace std;

int main() {
    double a,b,c,d,x;
    
    cin >> x >>a >> b >>c >> d ;
    printf("%.7f",a*x*x*x+b*x*x+c*x+d);
    
    return 0;
}

温度表达转化，http://noi.openjudge.cn/ch0103/08/[+]

#include <iostream>
#include<iomanip>
using namespace std;

int main() {
    double f;
    
    cin >> f ;
    //printf("%.7f",a*x*x*x+b*x*x+c*x+d);
    cout  << fixed << setprecision(5) << 5 * (f-32)/9 << endl;
    
    return 0;
}

与圆相关的计算，http://noi.openjudge.cn/ch0103/09/[+]

#include <iostream>
using namespace std;

int main() {
    double pi = 3.14159;
    double r;
    
    cin >> r ;
    printf("%.4f %.4f %.4f",2*r,2*pi*r,pi*r*r);
    
    return 0;
}

计算并联电阻的阻值，http://noi.openjudge.cn/ch0103/10/[+]

#include <iostream>
using namespace std;

int main() {
    float r1,r2;

    cin >> r1 >> r2 ;
    printf("%.2f",1/(1/r1+1/r2));

    return 0;
}

计算浮点数相除的余数，http://noi.openjudge.cn/ch0103/11/[+]

#include <iostream>
using namespace std;

int main() {
    double a,b;

    cin >> a >> b ;
    int c = (int)(a / b);
    printf("%g", a - b*c);

    return 0;
}

计算球的体积，http://noi.openjudge.cn/ch0103/12/[+]

#include <iostream>
using namespace std;

int main() {
    double pi = 3.14;
    double r;

    cin >> r ;
    printf("%.2f", 4 * pi * r*r*r/3);

    return 0;
}

反向输出一个三位数，http://noi.openjudge.cn/ch0103/13/[+]

#include <iostream>
using namespace std;

int main() {
    int n;

    cin >> n ;
    int h = n /100;
    printf("%d%d%d", (n - h * 100 )%10, (n - h * 100)/10, n/100 );

    return 0;
}

大象喝水，http://noi.openjudge.cn/ch0103/14/[+]

#include <iostream>
#include <cmath>
using namespace std;

int main() {
    double pi = 3.14159;
    double h,r;

    cin >> h >> r ;
    double v = pi * r * r * h / 1000;
    printf("%g", ceil(20/v) );

    return 0;
}

苹果和虫子，http://noi.openjudge.cn/ch0103/15/[+]

#include <iostream>
#include <cmath>
using namespace std;

int main() {
    double n,x,y;

    cin >> n >> x >> y ;
    printf("%g", n-ceil(y/x) );

    return 0;
}

计算线段长度，http://noi.openjudge.cn/ch0103/16/[+]

#include <iostream>
#include <cmath>
using namespace std;

int main() {
    double xa,ya;
    double xb,yb;

    cin >> xa >> ya;
    cin >> xb >> yb;
    printf("%.3f", sqrt(pow(xa-xb,2)+pow(ya-yb,2)) );

    return 0;
}

计算三角形面积，http://noi.openjudge.cn/ch0103/17/[+]

#include <iostream>
#include <cmath>
using namespace std;

int main() {
    double x1,y1,x2,y2,x3,y3;

    cin >> x1 >> y1 >> x2 >> y2 >> x3 >> y3;
    double l1 = sqrt(pow(x1-x2,2)+pow(y1-y2,2));
    double l2 = sqrt(pow(x2-x3,2)+pow(y2-y3,2));
    double l3 = sqrt(pow(x1-x3,2)+pow(y1-y3,2));
    double p = (l1 + l2 + l3) / 2;
    printf("%.2f", sqrt(p*(p-l1)*(p-l2)*(p-l3)));

    return 0;
}

等差数列末项计算，http://noi.openjudge.cn/ch0103/18/[+]

#include <iostream>
using namespace std;

int main() {
    int a1,a2,n;
    
    cin >> a1 >> a2 >> n;
    printf("%d", a1 + (n-1) * (a2-a1));

    return 0;
}

A*B问题，http://noi.openjudge.cn/ch0103/19/[+]

#include <iostream>
using namespace std;

int main() {
    long a,b;
    
    cin >> a >> b;
    cout << a * b << endl;
        
    return 0;
}

计算2的幂，http://noi.openjudge.cn/ch0103/20/[+]

#include <iostream>
#include <cmath>
using namespace std;

int main() {
    int n;

    cin >> n;
    int p = pow(2,n);
    cout << p << endl;
        
    return 0;
}

参考网址

http://noi.openjudge.cn